UrbanPro

Location Set your Location

Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Book a Free Demo

Class 10 > Learn Mathematics > Divide 20 into 4 parts which are in A.P. and such that...
✕

Search in

Divide 20 into 4 parts which are in A.P. and such that the product of first and fourth is to product of the second and third in ratio 2:3

Asked by Last Modified  

13 Answers

Learn Mathematics +2 Progressions Class IX-X Tuition

Follow 1
Answer

Please enter your answer

Dedicated Teacher With Lots of Teaching Experience In Maths For All Boards

Let the four terms of the AP = a -3d, a - d, a+d and a +3d. a -3d + a - d + a + d +a +3d = 20 4a = 20 a = 5 (a - 3d)(a +3d)/(a - d)(a + d) = 2/3 a2 - 9d2/a2 - d2 = 2/3 3(a2 - 9d2) = 2(a2 - d2) 3a2 - 27d2 = 2a2 - 2d2 a2 = 25d2 we have a = 5, substituting, we get 25 = 25d2 d2...
read more
Let the four terms of the AP = a -3d, a - d, a+d and a +3d. a -3d + a - d + a + d +a +3d = 20 4a = 20 a = 5 (a - 3d)(a +3d)/(a - d)(a + d) = 2/3 a2 - 9d2/a2 - d2 = 2/3 3(a2 - 9d2) = 2(a2 - d2) 3a2 - 27d2 = 2a2 - 2d2 a2 = 25d2 we have a = 5, substituting, we get 25 = 25d2 d2 = 25/25 d = 1 The four terms are a - 3d = 5 - 3 = 2, a - d = 5 - 1 = 4, a + d = 5 + 1 = 6 and a + 3d = 5 + 3 = 8 Ans; 2, 4, 6 and 8. check: 2 + 4 + 6 + 8 = 20 (2x 8)/(4 x 6) = 16/24 = 2/3 read less
Comments
Dislike Bookmark

Cat 97 percentiler with 96 marks in class 12 cbse board exam

Ans- 2,4,6,8 and 8,6,4,2 Let the four terms be a-3d,a-d,a+d,a+3d.. Then sum of all this will be 20 which will give 4a=20 or a=5 Following second part of the question (a-3d)(a+3d)/(a-d)(a+d) => a^2-9d^2 /a^2-d^2=2/3 25-9d^2 /25-d^2= 2/3 75- 27d^2=50- 2d^2 25=25d^2 D=+1 or d=-1 So sequence...
read more
Ans- 2,4,6,8 and 8,6,4,2 Let the four terms be a-3d,a-d,a+d,a+3d.. Then sum of all this will be 20 which will give 4a=20 or a=5 Following second part of the question (a-3d)(a+3d)/(a-d)(a+d) => a^2-9d^2 /a^2-d^2=2/3 25-9d^2 /25-d^2= 2/3 75- 27d^2=50- 2d^2 25=25d^2 D=+1 or d=-1 So sequence will be With d=+1 2,4,6,8 And with D=-1 8,6,4,2 read less
Comments
Dislike Bookmark

Math Educator for Std.11th ,12th , Engineering Entrance and Degree Level with 11+ Years Experience

2 , 4 , 6 , 8 2 x 8 = 16 and 4 x 6 = 24 so ratio 2 : 3
Comments
Dislike Bookmark

Mathematics Teacher

let us take 4 nos as x-(3a/2), x-(a/2), x+(3a/2), x+(a/2). adding these we get 4x=20, or, x=5. then acc to given condition, we get a=2. then putting all values we get all he 4 nos.
1 Comments
Dislike Bookmark

Tutor

let the four numbers to be the a-3d ,a-d, a+d ,a+3d as the numbers are in arithmetic progressions with common difference: 2d and (a-3d) +(a-d)+(a+d) +(a+3d)=20 we get 4a=20 a=5 (a-3d)(a+3d)/(a+d)(a-d)=2/3 (a-3d)(a+3d)*3=(a+d)(a-d)*2 i.e. 3a^2-27d^2=2a^2-2d^2 a^2=25d^2 :now substitute a=5 we...
read more
let the four numbers to be the a-3d ,a-d, a+d ,a+3d as the numbers are in arithmetic progressions with common difference: 2d and (a-3d) +(a-d)+(a+d) +(a+3d)=20 we get 4a=20 a=5 (a-3d)(a+3d)/(a+d)(a-d)=2/3 (a-3d)(a+3d)*3=(a+d)(a-d)*2 i.e. 3a^2-27d^2=2a^2-2d^2 a^2=25d^2 :now substitute a=5 we get 25=25d^2 d^2=1 d=+1,-1 so the numbers become 2,4,6,8 read less
1 Comments
Dislike Bookmark

Best Mathematics Teacher for Weak Students

let the numbers be a-3d,a-d,a+d,a+3d. a-3d+a-d+a+d+a+3d=20 a=5 (5-3d)(5+3d)/(5-d)(5+d)=2/3 25-9d2/25-d2 =2/3 75-27d2=50-2d2 25d2=25 d=1 or d=-1.....now proceed
Comments
Dislike Bookmark

Mathematics Expert for CBSE, ICSE, IGCSE, SSC Home & Group Tuition (VI-X)

2,4,6,8
Comments
Dislike Bookmark

Computer Language Professional

2,4,6,8
Comments
Dislike Bookmark

Math magician

let the numbers be a-3d, a-d, a+d, a+3d, given their sum is 20. a-3d+a-d+a+d+a+3d=20 after solving, a=5....(1) we know (a-3d)(a-3d)/(a-d)(a+d) = 2/3...(2) from (1), substitute the value of a in (2) by solving we will get d=+1 or -1 after substituting the values of a & d, we get the numbers...
read more
let the numbers be a-3d, a-d, a+d, a+3d, given their sum is 20. a-3d+a-d+a+d+a+3d=20 after solving, a=5....(1) we know (a-3d)(a-3d)/(a-d)(a+d) = 2/3...(2) from (1), substitute the value of a in (2) by solving we will get d=+1 or -1 after substituting the values of a & d, we get the numbers as 2,4,6,8 read less
1 Comments
Dislike Bookmark

Tutor

2,4,6,8
Comments
Dislike Bookmark

View 11 more Answers

Related Questions

If the areas of two similar triangles are in ratio 25 : 64, write the ratio of their corresponding sides.
5:8.
Priya
Is it necessary to join a tuition class in class 10?
It is not necessary but if you have any doubts, you should clear it with your family person or a tutor. If your basics are clear you can practice through reference books.
Harsha
0 0
7
What tuition is suggested in class 9 and 10?
Maths and science tuition is required
Neel
0 0
6
For what value of k, do the equations 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines?
The value of k should be equal to 2, and thus the equations, 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines
Aparna
What should a person do if he /she is struggling in maths in class 9?
First don't be panic, try to understand things practically and give time, do some mathematics and try to start your math with what you like most in mathematics topic and try to do these all things in two...
Rahul
0 0
5

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

What is difference between algorithm and log
Enter Learning Tip Content

Sakshi Goel

1 0
0
SURFCE AREA OF CONE
SURFACE AREA OF CONE If, r=radis of the cone l= slant height Then, 1)Curved Surface Area of the cone= πrl 2)Total surface Area...

Ramakrishna Dhooli

0 0
0
VOLUME OF THE CUBOID
VOLUME OF CUBOID:- If Length of Cuboid= l Breadth(width) of Cuboid= b Height of Cuboid= h Then, Volume of the cuboid= l x b x h cubic units Ex:- If Length of Cuboid= l = 15cm Breadth(width)...

Ramakrishna Dhooli

1 0
0
Trick to easily remember values of trigonometric ratios
Trigonometric ratios for class X: #Trick to remember values of trigonometric ratios of special Angles: 0° 30° 45° 60° 90° P 0 1 1 √3 1 B 1 √3 1 1 0 H 1 2 √2 2 1 now,...

Vishal Kumar Singh

0 0
0
Goods and Service Tax
Goods and Services Tax (GST)It is an indirect tax levied by the Central Government. In this tax ·there are so many taxesmerged such as Excise Duty, Customs Duty, Service Tax, Value Added Tax,Entertainment...

Bimal Upadhyay

1 0
0

Recommended Articles

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Quest Academy - Institute of the month

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Find Grade 10 Tuition near you
Grade 10 Tuition in Delhi
Grade 10 Tuition in Bangalore
Grade 10 Tuition in Hyderabad
Grade 10 Tuition in Kolkata
Grade 10 Tuition in Mumbai
Grade 10 Tuition in Chennai
Grade 10 Tuition in Pune
Grade 10 Tuition in Noida
Grade 10 Tuition in Lucknow
Grade 10 Tuition in Jaipur

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 10 Tuition with the Best Tutors

The best Tutors for Class 10 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2024All Rights Reserved